Page 409 - Emergency Response Book

Question: 19

A lead shield is used to block 60 Co radiation field of 96 Sv/hr. Calculate

the final dose rate after passing through 6.2 cm lead. Given, HVL for lead

in 60 Co is 1.24 cm.

Answer:

Given 1 HVL for lead is 1.24 cm, therefore 6.2 cm of lead is equivalent to

5 HVL

I

2 = o
n

I

x

96 96

2 = , therefore I = = 3  Sv / hr
5

I x 32

x

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