Page 320 - Radiation Safety

PROTECTION AGAINST EXTERNAL HAZARDS

(DISTANCE)

Solution

2
I d = I d 2
2 2
1 1

Given: I = 400µSv/hr
1

d 1 = 2 meter

I = 25µSv/hr
2

Therefore, 400 x (2) 2 = 25 x d 2

2
d2 = (400 x 4) /25 = 64

d2 = 8 meter

46